The correct option is A both of the above
Both reagents (1) tin(II) chloride and NaOH and (2) hypophosphorous acid in presence of cuprous ions will convert benzene diazonium chloride to benzene.
When benzene diazonium chloride is treated with benzene diazonium chloride with hypophosphorous acid in presence of cuprous ions, benzene is obtained.
C6H5N2Cl+H3PO2+H2OCu+−−→C6H6+H3PO3+HCl+N2
The reduction of benzene diazonium chloride with tin(II) chloride and NaOH gives benzene.
C6H5N2Cl+2[H]SnCl2/NaOH−−−−−−−−→C6H6+HCl+N2