Question

Which of the following relation is correct?

• A. $2I.P.-E.A.-E.N.=0$
• B. $2I.P.-E.N.-E.A.=0$
• C. $2E.N.-I.P.-E.A.=0$
• D. $E.N.-I.P.-E.A.=0$

Answer 1

The correct option is C $2E.N.-I.P.-E.A.=0$

When $E.N.$ stands for electronegetivity, $E.A.$ stands for electron affinity and $I.P.$ stands for Ionization potential.
It is observed that for an element, $E.A.$ and $E.N.$ and $I.P.$ usually vary in the same direction. Hence, when $E.A.$ and $E.N.$ and $I.P.$ also increases $E.N.$ has the mean valued of $I.P.$ and E.A.
$E.N.=$$\frac{I.P.+E.A.}{2}$
$\therefore$ $2E.N.=I.P.+E.N.$ or $2E.N.-I.P.-E.A.=0$