Which of the following relation is correct for the reaction $P C l_{5} (g) \to P C l_{3} (g) + C l_{2} (g)$

Δ H = Δ E

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Δ H > Δ E

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Δ H < Δ E

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Δ H = Δ E - R T

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Solution

The correct option is B $Δ H > Δ E$
$P C l_{5} (g) \to P C l_{3} (g) + C l_{2} (g)$
Here $Δ n_{g} = 1$
The relation between $Δ H$ and $Δ E$ is given by
$Δ H = Δ E + Δ n_{g} R T Δ H = Δ E + R T$
$∴ Δ H > Δ E$

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Similar questions

P C l_{5} (g) \to P C l_{3} (g) + C l_{2} (g),

P C l_{5} (g) \to P C l_{3} (g) + C l_{2} (g)

P C l_{5} (g) \to P C l_{3} (g) + C l_{2} (g)

P C l_{5} (g) \Leftrightarrow P C l_{3} (g) + C l_{2} (g), K_{c}

P C l_{5} (g) ⇌

P C l_{3} (g) + C l_{2} (g), K_{p} a n d K_{c}

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