You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Applications of Horizontal and Vertical Components

Which of the ...

Question

Which of the following relation is correct with respect to the angle with the horizontal at which an object should be projected so that the maximum height reached is equal to the horizontal range ?

tan θ = 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

tan θ = 4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

tan θ = \frac{2}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

θ = 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $tan θ = 4$
As per the given situation,
$R = H$
$\frac{u^{2} {sin}^{2} θ}{2 g} = \frac{u^{2} sin 2 θ}{g}$
$tan θ = 4$

Suggest Corrections

Similar questions

Q. A stone is thrown at an angle

θ

with the horizontal such that the horizontal range is equal to maximum height. The value of

tan θ

will be

Q. At what angle

(θ)

with the horizontal should a body be projected so that its horizontal range equals the maximum height it attains?

Q. A stone projected with a velocity

u

at an angle

θ

with the horizontal reaches maximum height

H_{1}

. When it is projected with velocity

u

at an angle

(\frac{π}{2} - θ)

with the horizontal, it reaches maximum height

H_{2}

. The relation between the horizontal range

R

of the projectile,

H_{1}

and

H_{2}

Q. A stone projected with a velocity with a velocity

u

at an angle

θ

with the horizontal reaches maximum height

H_{1}

. When it is projected with the velocity

u

at an angle

(\frac{π}{2} - θ)

with the horizontal, it reaches maximum height

H_{2}

. The relation between the horizontal range

R

of the projectile, heights

H_{1}

and

H_{2}

Q. A stone projected with a velocity

u

at an angle

θ

with the horizontal reaches maximum height

H_{1}

. When it is projected with velocity

u

at an angle

(\frac{π}{2} - θ)

with the horizontal, it reaches the maximum height

H_{2}

. The relation between the horizontal range

R

of the projectile,

H_{1}

and

H_{2}

Join BYJU'S Learning Program

Which of the following relation is correct with respect to the angle with the horizontal at which an object should be projected so that the maximum height reached is equal to the horizontal range ?

The correct option is B tan θ=4As per the given situation, R=H u2 sin2 θ2g=u2 sin 2θg tan θ=4

The correct option is B $tan θ = 4$
As per the given situation,
$R = H$
$\frac{u^{2} {sin}^{2} θ}{2 g} = \frac{u^{2} sin 2 θ}{g}$
$tan θ = 4$