You visited us 4 times! Enjoying our articles? Unlock Full Access!

Towards Biot-Savart Law

Which of the ...

Question

Which of the following relation represents Biot-Savart's law?

\to d B = \frac{μ_{0}}{4 π} \frac{\to d l \times \to r}{r}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\to d B = \frac{μ_{0}}{4 π} \frac{\to d l \times^r}{r^{3}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\to d B = \frac{μ_{0}}{4 π} \frac{\to d l \times \to r}{r^{3}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\to d B = \frac{μ_{0}}{4 π} \frac{\to d l \times \to r}{r^{4}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\to d B = \frac{μ_{0}}{4 π} \frac{\to d l \times \to r}{r^{3}}$
If unit current is flowing through the conductor, then Biot-Savart's law is represented as
$\to d B = \frac{μ_{0}}{4 π} \frac{\to d l \times \to r}{r^{3}}$

Suggest Corrections

Similar questions

\to d B

\to r

\to d l

\to d B

\to r

\to d l

A C

B D

A B C D

\to A B + \to D C = \to A C + \to D B

B_{v} = \frac{μ_{0}}{4 π} \frac{2 m c o s θ}{r^{3}}

B_{H} = \frac{μ_{0}}{4 π} \frac{m s i n θ}{r^{3}}

θ = 90^{0}

45^{0}

\to j

- \to d B = \frac{μ_{0}}{4 π} .

\frac{\to j \times \to r}{r^{3}}

d V

Join BYJU'S Learning Program