Question

Which of the following relations are correct?

• A. 1 e V = 9.11 $\times$ ${10}^{-4}$ J
• B. 1 L = 1 d $m^3$
• C. 1 J = 1.98 cal
• D. 1 atm = 1.01325 bars

Answer 1

Answer: (B), (D)

1 atm = 1.01325 bars

(b) 1 L = 1000 ${cm}^3$ = ${10}^3$ $\times$ ${\left({10}^{-2}\right)}^3$ $m^3$ = ${10}^{-3}$ $m^3$ = 1 d $m^3$

(d) 1 atm = 1.01325 bar = 1.01325 $\times$ ${10}^5$ Pa = 101325 Pa