Which of the following relations hold good for 'R' and 'F', where 'R' is the radius of curvature of a spherical mirror and 'F' is the focal length of the mirror?

R = F

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$R = \frac{F}{2}$

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$F = \frac{R}{2}$

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2F = R

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Solution

The correct options are
C
$F = \frac{R}{2}$

D
2F = R

The focal point occurs at the midpoint between pole and radius of curvature. So, if radius of curvature is $R$ and focus is $F$ , then, $F = \frac{R}{2}$ or $2 F = R$ .

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If R is the radius of curvature of a spherical mirror and f is its focal length, then : (a) R = f (b) R=2f (c) R= $\frac{f}{2}$ (d) R=3f

Which of the following relations hold good for 'R' and 'F', where 'R' is the radius of curvature of a spherical mirror and 'F' is the focal length of the mirror?

For a spherical mirror, the radius of curvature $R$ and focal length $f$ are correlated as,

Q. What is the relationship between the focal length

f

and radius of curvature

R

for a spherical mirror?

Which of the following relations hold good where F is the focal length and R is the radius of curvature.

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Which of the following relations hold good for 'R' and 'F', where 'R' is the radius of curvature of a spherical mirror and 'F' is the focal length of the mirror?

The correct options are C F=R2 D 2F = R The focal point occurs at the midpoint between pole and radius of curvature. So, if radius of curvature is R and focus is F, then, F=R2 or 2F=R.

The correct options are
C
$F = \frac{R}{2}$

D
2F = R

The focal point occurs at the midpoint between pole and radius of curvature. So, if radius of curvature is $R$ and focus is $F$ , then, $F = \frac{R}{2}$ or $2 F = R$ .