The correct options are
A ΔG=ΔH−TΔS
B ΔG=ΔH+T[δ(ΔG)δT]P
Gibbs Helmholtz Equation :
dG=VdP−SdT
at constant pressure
dG=−SdT
⇒(dGdT)p=−S
(δΔGδT)p=−ΔS (1)
and
G=H−TS⇒G−HT=−S
=(dGdT)p
Substituting in G=H−TS, we get
G=H+T(dGdT)p
we can write this as
ΔG=ΔH+T(δΔGδT)p
ΔG=ΔH+TΔS
So option a and b are only correct.