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Question

Which of the following relations is correct?

A
r=mvqB
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B
r=qBmv
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C
r=mqvB
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D
r=mBqv
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Solution

The correct option is A r=mvqB
When a charged particle of charge q and mass m is projected with velocity v in a uniform magnetic field B perpendicularly, then it moves in a circular path of radius r.
Now, Centripetal force = Magnetic force
mv2r=qvB
r=mvqB
Hence, the correct answer is option (1).

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