Which of the following relations is incorrect for solutions with respect to their colligative properties?

$3 N A l_{2} (S O_{4})_{3} = 0.5 M A l_{2} (S O_{4})_{3}$

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$3 M H_{2} S O_{4} = 6 N H_{2} S O_{4}$

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$1 M H_{3} P O_{4} = \frac{1}{3} N H_{3} P O_{4}$

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$1 M A l_{2} (S O_{4})_{3} = 6 N A l_{2} (S O_{4})_{3}$

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Solution

The correct option is C
$1 M H_{3} P O_{4} = \frac{1}{3} N H_{3} P O_{4}$

Normality = Molarity $\times n_{f}$

For $A l_{2} (S O_{4})_{3}, n_{f}$ is 6

For $H_{2} S O_{4}, n_{f}$ is 2

For $H_{3} P O_{4}, n_{f}$ is 3

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