Which of the following represent correct order of conductivity in solids ?

(a) $K_{m e t a l s} >> K_{i n s u l a t o r s} < K_{s e m i c o n d u c t o r s}$

(b) $K_{m e t a l s} << K_{i n s u l a t o r s} < K_{s e m i c o n d u c t o r s}$

(c) $K_{m e t a l s} ., K_{s e m i c o n d u c t o r s} > K_{i n s u l a t o r s} = z e r o$

(d) $K_{m e t a l s} < K_{s e m i c o n d u c t o r s} > K_{i n s u l a t o r s} \neq z e r o$

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Solution

Answer: (a) The conductivity of metal, insulator, and semiconductors can be represented in the form of k (kappa ) which depends upon the energy gap between the valence band and the conduction band.

Hence, correct order is

$K_{m e t a l s} >> K_{i n s u l a t o r s} < K_{s e m i c o n d u c t o r s}$

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