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Question

Which of the following represent the correct electronic configuration of O2?


A

(σ1s)2 (σ1s)2 (σ2s)2 (σ2s)2 (σ2pz)2 (π2px2π2py2) (π2px1π2py1)

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B

(σ1s)2 (σ1s)2 (σ2s)2 (σ2s)2 (σ2pz)2 (π2px2π2py2) (π2px2)

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C

(σ1s)2 (σ1s)2 (σ2s)2 (σ2s)2 (σ2pz)2 (π2px2π2py2) (π2py2)

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D

(σ1s)2 (σ1s)2 (σ2s)2 (σ2s)2 (σ2pz)2 (π2px2π2py2) (π2py2)

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Solution

The correct option is A

(σ1s)2 (σ1s)2 (σ2s)2 (σ2s)2 (σ2pz)2 (π2px2π2py2) (π2px1π2py1)


To write the electronic configuration of O2,

First we have to draw the energy level diagram (MOT) for O2

While filling the electrons in the energy levels, we have to follow the rules for filling the electrons.

The energy level diagram of O2 will be:

O2 Dioxygen Paramagnetic; Coloured

O22+ Diamagnetic; Colourless

O22 Peroxide Diamagnetic; Colourless

O2+ Paramagnetic; Coloured

O2 Superoxide Paramagnetic; Coloured

Now,

As we can see from the diagram, the electrons present in different energy levels are:

σ1s 2 electrons, σ1s 2 electrons, σ2s 2 electrons,

σ1s 2 electrons, σ2pz 2 electrons

π2px 2 electrons, π2py 2 electrons

π2px 1 electrons, π2py 1 electrons

So, the electronic configuration will be:

O2 (σ1s)2 (σ1s)2 (σ2s)2 (σ2s)2 (σ2pz)2 (π2px2π2py2) (π2px1π2py1)

[*Note we know, in p - orbitals, σ bond will be formed by Z-axis (i.e., pz), but π bond can be formed either by x or y, that's why they are shown in one single bracket]


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