The correct option is B ECl2/Cl−=E0Cl2/Cl−−0.059 log[Cl−]
In the given cell representation, the gas is indicated before the electrode. Hence, it is a cathode half cell where the reduction reaction occurs.
Thus, the half cell reaction is,
12Cl2(g)+e−⇋Cl−(aq) (reduction)
(1 atm)
Nernst equation for
aA+bB⇋cC+dD
E=E0−2.303RTnFlog[C]c[D]d[A]a[B]b.....(Eqn.1)
Substituting,
R=8.314 J K−1 mol−1
F=96500 C
T=25+273=298 K, we get,
E=E0−0.059nlog[C]c[D]d[A]a[B]b....(Eqn.2)
where,
n is the number of electrons inovolved in the reaction.
12Cl2(g)+e−⇋Cl−(aq) (reduction)
(1 atm)
ECl2/Cl−=E0Cl2/Cl−−0.0591log[Cl−][Cl2]12
ECl2/Cl−=E0Cl2/Cl−−0.059 log[Cl−]