Question

Which of the following represents $14$ minutes before $10$ on an analog clock?

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

The given time is $14$ minutes before $10.$
We know that there are $60$ minutes in an hour.
$60-14=46$ min
So, the given time can also be written as $46$ minutes after $9.$

The time is $46$ minutes after $9,$ indicating that it is after $9$ o’clock, but before $10$ o’clock.
So, the hour hand will lie between $9$ and $10.$

$46$ minutes can be written as $45+1$ .
We know that the space between any two consecutive numbers on an analog clock is $5$ minutes.
$9\times 5=45$ minutes
So, $9$ represents $45$ minutes on the clock, so the minute hand will lie after $9.$
We have $1$ more minute after $45,$ which means the minute hand will cover $1$ division after $9.$

So, the hour hand will lie after $9$, but before $10$.
The given time which is $46$ minutes is more than $30$ minutes (half an hour). So, the hour hand will be located closer to $10$.
The minute hand will be at the ${46}^{th}$ division from $12.$
We can also say that the minute hand will be $1$ division ahead of $9.$

So, the clock which represents $14$ minutes before $10$ is: