Which of the following represents the above figure correctly:

$\frac{3}{8} + \frac{5}{8} = \frac{2}{8}$

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$\frac{3}{8} + \frac{2}{8} = \frac{5}{8}$

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$\frac{3}{8} - \frac{5}{8} = \frac{2}{8}$

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$\frac{3}{8} - \frac{2}{8} = \frac{1}{8}$

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Solution

The correct option is B
$\frac{3}{8} + \frac{2}{8} = \frac{5}{8}$

As we can see in the above figure, the circles are divided into eight equal parts.

In the first circle, three parts are shaded. So, the fraction represented by the first circle = $\frac{3}{8}$

In the second circle, two parts are shaded. So, the fraction represented by the second circle = $\frac{2}{8}$

In the third circle, five parts are shaded. So, the fraction represented by the third circle = $\frac{5}{8}$

Now, $\frac{3}{8} + \frac{2}{8} = \frac{5}{8}$

Hence, the above figure represents the equation:

$\frac{3}{8} + \frac{2}{8} = \frac{5}{8}$

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Similar questions

1 + \frac{2}{3} (\frac{1}{8}) + \frac{2 \times 5}{3 \times 6} {(\frac{1}{8})}^{2} + \frac{2 \times 5 \times 8}{3 \times 6 \times 9} {(\frac{1}{8})}^{3} + . . . .

A = 4 + \frac{5}{8} + \frac{6}{8^{2}} + \frac{3}{8^{3}} + \frac{7}{8^{4}} a n d B = 4 + \frac{5}{8} + \frac{5}{8^{2}} + \frac{7}{8^{3}} + \frac{6}{8^{4}} .

8^{3} \times 8^{2} \times 8^{- 5}

{(\frac{5}{8})}^{- 7} \times {(\frac{8}{5})}^{- 5}

\frac{(2^{5})^{2} \times 7^{3}}{8^{3} \times 7}

8^{3} \times 8^{2} \times 8^{- 5}

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