Which of the following represents the anode half-cell reaction for the following galvanic cell: $C u (s) | C u^{2 +} (a q) | | A g^{+} (a q) | A g (s)$

$C u (s) + 2 A g^{+} (a q) \to C u^{2 +} (a q) + 2 A g (s)$

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$C u (s) \to C u^{2 +} (a q) + 2 e^{-}$

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$2 A g^{+} (a q) + 2 e^{-} \to 2 A g (s)$

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$A g^{+} (a q) + e^{-} \to A g (s)$

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Solution

The correct option is B
$C u (s) \to C u^{2 +} (a q) + 2 e^{-}$

Reduction reaction takes place at cathode and oxidation reaction takes place at anode.
Cathode $: 2 A g^{+} (a q) + 2 e^{-} \to 2 A g (s)$
Anode $: C u (s) \to C u^{2 +} (a q) + 2 e^{-}$
Cell reaction $: C u (s) + 2 A g^{+} (a q) \to C u^{2 +} (a q) + 2 A g (s)$

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Similar questions

C u (s) | C u^{2 +} (a q) | | A g^{+} (a q) | A g (s)

C u_{(s)} \to C u_{(a q)}^{2 +} + 2 e^{-}; E^{o} = - 0.325 V

C u_{(a q)}^{+} + e^{-} \to C u_{(s)}; E^{o} = 0.50 V

E^{o}

2 C u_{(a q)}^{+} \to C u_{(a q)}^{2 +} + C u_{(s)}

C u (s) + 2 A g^{+} (a q .) \to C u^{2 +} (a q .) + 2 A g (s)

E_{c e l l}^{\circ} = 0.46 V

C u^{2 +}, E_{c e l l}^{\circ}

C u S O_{4}

C u (s) + 2 A g^{+} (a q .) ⇌ C u^{2 +} (a q .) + 2 A g (s)

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