Question

Which of the following represents the correct order of stabilities?

• A. $S{c}^{2+}>S{c}^{3+}$
• B. $T{i}^{2+}>T{i}^{4+}$
• C. $T{i}^{4+}>T{i}^{3+}$
• D. All of the above

Answer 1

The correct option is C $T{i}^{4+}>T{i}^{3+}$

Lower members of the $3d$ series tend to lose more electrons. Maximum possible oxidation state is the most stable oxidation state because, they attained the nearest noble gas configuration which make the ions stable.
Maximum possible oxidation state of $Sc$ is $+3$ and $Ti$ is $+4$.
$S{c}^{3+}andT{i}^{4+}$ attains the configuration of $Ar$ and becomes stable.
Hence, $\left(c\right)$ is the correct answer.