Question

Which of the following represents the correct order of the negative inductive effect?

• A. (i)>(ii)
• B. (i)<(ii)
• C. (i)=(ii)
• D. None of the above

Answer 1

The correct option is B (i)<(ii)

In (i) the C is $s{p}^2$ hybridised and in (ii) the C is $sp$ hybridised.

More the % s-character means more electronegativity of the attached carbon, so more will be -I. So in between $sp$ and $s{p}^2$, sp is the most electronegative because of more $\%$ s-character.

So the correct answer will be option(b).