Which of the following represents the correct order of the negative inductive effect?

(i)>(ii)

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(i)<(ii)

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(i)=(ii)

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None of the above

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Solution

The correct option is B (i)<(ii)
In (i) the C is $s p^{2}$ hybridised and in (ii) the C is $s p$ hybridised.

More the % s-character means more electronegativity of the attached carbon, so more will be -I. So in between $s p$ and $s p^{2}$ , sp is the most electronegative because of more $%$ s-character.

So the correct answer will be option(b).

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Similar questions

The order of -I power (-ve inductive effect ) of the following functional groups will be:

(i) $- S O_{3} H$

(ii) $- C l$

(iii) $- N H_{2}$

(iv) $- H$

(i) C H_{3} - + C H - C H_{2} - O C H_{3}

(i i) C H_{3} - + C H - C H_{2} - C H_{3}

(i i i) C H_{3} - + C H - O | | C - C H_{3}

The order of -I power (-ve inductive effect ) of the following functional groups will be:

(i) $- S O_{3} H$

(ii) $- C l$

(iii) $- N H_{2}$

(iv) $- H$

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