Which of the following represents the products obtained when $Z n$ reacts with $N a O H$ ?

N a_{2} Z n O_{2} + H_{2}

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N a_{2} O + Z n O + H_{2} O

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N a_{2} Z n O_{2} + H_{2} O

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N a + Z n O + H_{2}

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Solution

The correct option is A $N a_{2} Z n O_{2} + H_{2}$
$Reason$ : Zinc( $Z n$ ) is a amphoteric metal and sodium hydroxide( $N a O H$ ) is a base.Very few metals react with base and according to the reactivity chart, the reactivity of zinc is lower than the sodium, so, zinc can reacts with the aqueous solution of sodium hydroxide( $N a O H$ ).

When zinc metal reacts with sodium hydroxide, the following reaction takes place -

$Z n (s)$ + $2 N a O H (a q)$ $\to$ $N a_{2} Z n O_{2} (a q)$ + $H_{2} (g)$

After this reaction, we get sodium zincate( $N a_{2} Z n O_{2}$ ) as a product with the evolution of hydrogen( $H_{2}$ ) gas.This reaction takes place at a temperature near $550^{o} C$ .

Hence, the correct option is $A$

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