Which of the following represents the relative penetrating power of the three types of radioactive emission in decreasing order?

β > α > γ

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β > γ > α

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γ > α > β

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γ > β > α

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Solution

The correct option is D $γ > β > α$
Penetrating power depends on the ionizing power of the rays. More the ionizing power, less is the ray able to get into the material.
Since alpha rays have the highest penetrating power. This means that if a given number of alphas are fired at a target they will all cause ionization near the surface of the material, resulting in the effects of the radiation being concentrated in a small volume. Thus they have smallest penetrating power.
Beta rays have a higher penetrating power due to lower ionizing power, and gamma rays have the highest penetrating power.

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Q. If

α, β, γ

are the roots of

a x^{3} + b x^{2} + c x + d = 0

and

∣ ∣ ∣ ∣ ∣ \begin{matrix} α & β & γ β & γ & α γ & α & β \end{matrix} ∣ ∣ ∣ ∣ ∣ = 0

α \neq β \neq γ

, then find the equation whose roots are

α + β - γ, γ + α - β, β + γ - α

In each of $α$ $β$ and $γ$ $is a positive acute angle such that$
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Find the values of $α$ , $β$ , & $γ$ .

Q. lf

α, β, γ

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x^{3} + 2 x - 3 = 0

, then the transformed equation having the roots

\frac{α}{β} + \frac{β}{α}, \frac{β}{γ} + \frac{γ}{β}, \frac{γ}{α} + \frac{α}{γ}

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x =

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