Which of the following salt solution has the lowest $p H$ ?

K_{2} C_{2} O_{4}

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{(N H_{4})}_{2} S O_{4}

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K_{2} S O_{4}

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N a N O_{3}

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Solution

The correct option is B ${(N H_{4})}_{2} S O_{4}$
The solution should be acidic for low $p H$ .
$K_{2} C_{2} O_{4} \to 2 K^{+} + C_{2} O_{4}^{2 -}$
$C_{2} O_{4}^{2 -} + 2 H_{2} O \to H_{2} C_{2} O_{4} + 2 O H^{-}$
$(N H_{4})_{2} S O_{4} \to 2 N H_{4}^{+} + S O_{4}^{2 -}$
$N H_{4}^{+} + H_{2} O \to N H_{4} O H + H^{+}$
It is acidic due to the generation of $H^{+}$ , therefore it has the lowest $p H$ .
$N a N O_{3}$ is neutral since it is formed from a strong acid and strong base.

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