Question

Which of the following samples of reducing agents is/are chemically equivalent to 25 ml of 0.2 N $KMn{O}_4$ to be reduced to $M{n}^{2+}$ and water?

• A. 25 ml of 0.2 M $FeS{O}_4$ to be oxidized to $F{e}^{3+}$
• B. 50 ml of 0.1 M $H_{3}As{O}_3$ to be oxidized to $H_{3}As{O}_4$
• C. 25 ml of 0.1 M $H_2{O}_2$ to be oxidized to $H^{+}$ and $O_2$
• D. 25 ml of 0.1 M $SnC{I}_2$ to be oxidized to $S{n}^{4+}$

Answer 1

Answer: (A), (D)

25 ml of 0.2 M $FeS{O}_4$ to be oxidized to $F{e}^{3+}$
25 ml of 0.1 M $SnC{I}_2$ to be oxidized to $S{n}^{4+}$

Milliequivalent of $KMn{O}_4=25\times 0.2=5$
Milliequivalent of $FeS{O}_4=25\times 0.2=5$
Milliequivalent of $SnC{l}_2=25\times 0.1\times 2=5$
Hence, the samples of options A and D are chemically equivalent to 25 ml of 0.2 N $KMn{O}_4$ to be reduced to $M{n}^{2+}$ and water.