Which of the following satisfies the equation a2b2x2−b2x−a2x+1=0?
−1b2
1b2
±1b2
−1a2
a2b2x2−b2x−a2x+1=0 ⇒b2x(a2x−1)−1(a2x−1)=0 ⇒(a2x−1)(b2x−1)=0 ⇒x=1a2,1b2