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Question

Which of the following sequence is correct for solubility in H2O?
(1) BeSO4>MgSO4>CaSO4>BaSO4
(2) Be(OH)2>Mg(OH)2>Ca(OH)2>Ba(OH)2
(3) LiOH<NaOH<KOH<RbOH
(4) Li2CO3<Na2CO3<K2CO3<Rb2CO3

A
1, 3, 4
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B
1, 2, 4
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C
2, 4
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D
1, 3, 4
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Solution

The correct option is A 1, 3, 4
Sulphate ion is a large size ion. So more the size of cation more will be the interaction in the compound. More interaction leads to more lattice energy and the solubility decreases.
So, solubility decreases on moving top to bottom in the group.
So, solubility of alkaline earth metals are BeSO4>MgSO4>CaSO4>BaSO4

Similarly OH ion is a small size ion. So more the size of cation less will be the interaction in the compound. Less interaction leads to lesser lattice energy and the solubility increases.
So, solubility increases on moving top to bottom in the group.
So, option B will be incorrect.
But option C will be correct.
LiOH<NaOH<KOH<RbOH

The option d has a different case. Though CO23 a large size ion, the solubility increases on moving top to bottom in the group.
This is due to the special structure of the alkaline carbonates. The alkali metal ions fit inside the carbonate ion like the structure below.

(M+=cation of alkali metal ions)
More will be the size of the cation lesser fit will be the alkali ions in the carbonate ion. Less fit the alkali ions more will be the solubility.

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