Which of the following sequence is correct with reference to the oxidation number of iodine?

I_{2} < I C l < H I < H I O_{4}

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H I O_{4} < I C l < I_{2} < H I

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I_{2} < H I < I C l < H I O_{4}

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H I < I_{2} < I C l < H I O_{4}

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Solution

The correct option is A $H I < I_{2} < I C l < H I O_{4}$
Compound Oxidation state of Iodine
$I_{2}$ $0$
$I C l$ $+ 1$
$H I$ $- 1$
$H I O_{4}$ $+ 7$
Hence, the correct sequence is $H I < I_{2} < I C l < H I O_{4}$ .

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