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Question

Which of the following sequence(s) is/are correct for solubility in H2O?
(1) BeSO4>MgSO4>CaSO4>BaSO4
(2) Be(OH)2>Mg(OH)2>Ca(OH)2>Ba(OH)2
(3) LiOH<NaOH<KOH<RbOH
(4) Li2CO3<Na2CO3<K2CO3<Rb2CO3

A
1,3,4
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B
1,2,4
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C
2,4
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D
1,3
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Solution

The correct option is A 1,3,4
The anions can be divided into two set of ions on the basis of size, i.e. smaller size (e.g. OH, O2, N3 etc.) and larger size (e.g. SO24, NO3 etc.).
The smaller sized anions fit better in the lattice with the smaller cations which results in more lattice enthalpy.
So, on moving down the group, the lattice energy of the compounds with smaller size anions goes on decreasing and solubility increases down the group.
Be(OH)2<Mg(OH)2<Ca(OH)2<Ba(OH)2
LiOH<NaOH<KOH<RbOH

The larger sized anions fit better in the lattice with the larger cations which results in more lattice enthalpy.
So, on moving down the group, the lattice energy of the compounds with larger size anions goes on increasing and solubility decreases down the group.
BeSO4>MgSO4>CaSO4>BaSO4

Solubility of the carbonates increases down the group due to decrease in lattice energy.
Li2CO3<Na2CO3<K2CO3<Rb2CO3

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