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Question

Which of the following sequences is correct for decreasing order of ionic radius?

A
Se2>I>Br>O2>F
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B
I>Se2>O2>Br>F
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C
Se2>I>Br>F>O2
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D
I>Se2>Br>O2>F
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Solution

The correct option is D I>Se2>Br>O2>F
The size increases with increasing number of shells, irrespective of the charge. And if number of shells are same, more negative ion is larger. Thus correct order is
I>Se2>Br>O2>F

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