The correct option is C Ionic radius: F−>O2−>H−
a) Standard reduction potential of halogens are positive and decrease down the group. The oxidising power also decreases down the group.
b) Generally bond energy decreases down the group as the size increases but in F2, interelectronic repulsion is very high, it has a lower bond energy as compared to Cl2, Br2.
c) Ionic radius increases with an increase in the negative charge. So, F− should have a lower ionic radius compared to O2−.
d) Electron affinity of O is lower than S and Se because of a high interelectronic repulsion in O.