The correct option is B CH3CH2COOCH3>(CH3)2CHCOOCH3>(CH3)3CCOOCH3
The hydroxide nucleophiles attack at the electrophilic C of the ester C=O, break the pi bond and create a tetrahedral intermediate. Esters with more electrophilic CO would be more reactive. The increasing inductive effect decreases the electrophilc character of CO, therefore the order of rate of alkaline hydrolysis of esters is CH3CH2COOCH3>(CH3)2CHCOOCH3>(CH3)3CCOOCH3