Which of the following set have same bond order value?

C O, C N^{-} a n d N O^{+}

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C N^{-}, C O^{+} a n d N_{2}

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N O^{-}, C O a n d C N^{-}

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N_{2}, C O_{3}^{- 2} a n d C N^{-}

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Solution

The correct option is A $C O, C N^{-} a n d N O^{+}$
According to molecular orbital theory, Bond order are obtained by the following formula.
$\frac{N_{b} - N_{a}}{2}$
where, $N_{b}$ = No. of electrons in bonding molecular orbital
$N_{a}$ = no. of electrons in antibonding molecular orbital
From Mo energy diagram, electronic configuration of $C O, C N^{-}$ and $N O^{+}$ is,
$(σ 2 s)^{2} (σ^{*} 2 s)^{2} (π 2 p x)^{2} (π 2 p y)^{2} (σ 2 p z)^{2}$
Bond order $= N_{b} - N_{a} / 2$
$= \frac{8 - 2}{2} = 3$
So, the correct answer is option $^{'} A^{'}$

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