Question

Which of the following set of quantum number represents highest energy of an atom?

• A. n=3, l=2, m=1, s=$+\frac{1}{2}$
• B. n=3, l=2, m=1, s=$-\frac{1}{2}$
• C. n=4, l=0, m=0, s=$+\frac{1}{2}$
• D. n=3, s=$+\frac{1}{2}$

Answer 1

Answer: (A)

n=3, l=2, m=1, s=$+\frac{1}{2}$

Higher the $n+l$ value higher is the energy. But in case of same $n+l$ value as in option A and B. Spin up $(S=+1/2)$ has slightly greater energy than $(S=-1/2)$

Option A is correct.