Which of the following set of quantum numbers is an impossible arrangement?

n = 3, m = - 2, s = + 1 / 2

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n = 4, m = 3, s = + 1 / 2

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n = 5, m = 2, s = - 1 / 2

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n = 3, m = - 3, s = - 1 / 2

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Solution

The correct option is D $n = 3, m = - 3, s = - 1 / 2$
$n = 1, 2, 3....$

$l = 0, 1, 2.... (n - 1)$ ex- if $n = 3, l = 0, 1, 2$

$m = - l t o l$

$s = + 1 / 2, - 1 / 2$

$n$ $\neq$ $m$ So, the following configuration is not possible.

$n = 3, m = - 3, s = - 1 / 2$
Option D is correct.

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Similar questions

Which of the following sets of quantum numbers is correct for an electron in 4f orbital?

4 f -

n = 4, l = 0, m = 0, s = + \frac{1}{2}

n = 3, l = 1, m = 1, s = - \frac{1}{2}

n = 3, l = 2, m = 0, s = + \frac{1}{2}

n = 3, l = 0, m = 0, s = - \frac{1}{2}

n = 4, l = 2, m_{1} = - 2, m_{s} = - 1 / 2

n = 3, l = 2, m_{1} = 1, m_{s} = + 1 / 2

n = 4, l = 1, m_{1} = 0, m_{s} = + 1 / 2

n = 3, l = 2, m_{1} = - 2, m_{s} = - 1 / 2

n = 3, l = 1, m_{1} = - 1, m_{s} = + 1 / 2

n = 4, l = 1, m_{1} = 0, m_{s} = + 1 / 2

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