Question

Which of the following set of quantum numbers is an impossible arrangement?

• A. $n=3,m=-2,s=+1/2$
• B. $n=4,m=3,s=+1/2$
• C. $n=5,m=2,s=-1/2$
• D. $n=3,m=-3,s=-1/2$

Answer 1

The correct option is D $n=3,m=-3,s=-1/2$

$n=1,2,\mathrm{3....}$

$l=0,1,\mathrm{2....}(n-1)$ ex- if $n=3,l=0,1,2$

$m=-ltol$

$s=+1/2,-1/2$

$n$ $\ne$ $m$ So, the following configuration is not possible.

$n=3,m=-3,s=-1/2$
Option D is correct.