Question

Which of the following set of quantum numbers is correct for an electron in 6f orbital?

• A. $n=6,l=5,m=2,s=+\frac{1}{2}$
• B. $n=6,l=4,m=3,s=+\frac{1}{2}$
• C. $n=6,l=3,m=2,s=+\frac{1}{2}$
• D. $n=6,l=3,m=4,s=+\frac{1}{2}$

Answer 1

The correct option is C $n=6,l=3,m=2,s=+\frac{1}{2}$

For an electron in 6f orbital,
$n=6$ and $l=3$.
m can have any value from $-3$ to $+3$
and s can be $+\frac{1}{2}$ or $-\frac{1}{2}$.
So, the only possible set of quantum numbers for an electron in the 6f orbital from the given options is $n=6,l=3,m=2,s=+\frac{1}{2}$.