Which of the following set of species have planner structures?

I_{3}^{-}, C H_{3}, C l O_{3}^{-}, S i F_{6}^{2}

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I_{3}^{+}, I C l_{4}^{-}, A l_{2} C l_{6}, T e C l_{4}

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S C l_{2}^{-}, N_{2} O_{5}, S F_{4}, X e O F_{4}

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I_{3} C l_{6}, X e F_{2}, B r F_{4}^{-}, X e F_{5}^{-}

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Solution

The correct option is B $I_{3}^{-}, C H_{3}, C l O_{3}^{-}, S i F_{6}^{2}$
wrong question.
In $I_{3}^{-}$ three lone pair of electrons have equivalent interactions with the three iodine atoms so there is no deviations in bonding angles.
In ${C H}_{3}$ there is three bonding pairs and one lone pair. It is a planner structure.
In ${S i F}_{6}^{2}$ it is $d^{2} {s p}^{3}$ hybridised and contain no lone pair.
In $C l O_{3}^{-}$ it is a trigonal planner molecule

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