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Which of the ...

Question

Which of the following sets includes only transition elements?

z = 11, 14, 22, 42

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z = 13, 33, 54, 83

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z = 24, 39, 74, 80

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z = 19, 32, 51, 101

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Solution

The correct option is C
z = 24, 39, 74, 80

There are four series of transition elements
$I s e r i e s_{21 - 30}^{S c - Z n}; I I s e r i e s_{39 - 48}^{Y - C d}; I I I s e r i e s_{57^{'} 72 - 80}^{L a H f - H g} I V s e r i e s_{89104}^{A c, R f} -$

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Similar questions

\frac{- 5}{16} \times \frac{8}{15} = \frac{8}{15} \times \frac{- 5}{16}

\frac{- 17}{5} \times 9 = 9 \times \frac{- 17}{5}

\frac{7}{4} \times (\frac{- 8}{3} + \frac{- 13}{12}) = \frac{7}{4} \times \frac{- 8}{3} + \frac{7}{4} \times \frac{- 13}{12}

\frac{- 5}{9} \times (\frac{4}{15} \times \frac{- 9}{8}) = (\frac{- 5}{9} \times \frac{4}{15}) \times \frac{- 9}{8}

\frac{13}{- 17} \times 1 = \frac{13}{- 17} = 1 \times \frac{13}{- 17}

\frac{- 11}{16} \times \frac{16}{- 11} = 1

\frac{2}{13} \times 0 = 0 = 0 \times \frac{2}{13}

\frac{- 3}{2} \times \frac{5}{4} + \frac{- 3}{2} \times \frac{- 7}{6} = \frac{- 3}{2} \times (\frac{5}{4} + \frac{- 7}{6})

54 / 32 = 4, 39 / 42 = 3, 92 / 22 = 7

28 / 33 =

45

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6

30

75

42, 21, 50, 37, 42, 37, 38, 42, 49, 52, 38, 53, 57, 47, 29

59, 61, 33, 17, 17, 39, 44, 42, 39, 14, 7, 27, 19, 54, 51

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