Which of the following sets of quanta numbers could represent the last electron added to complete the electronic configuration for a ground state atom of Br (Z = 35)?

4, 0, 0, - \frac{1}{2}

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4, 1, 1, - \frac{1}{2}

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3, 1, 1, - \frac{1}{2}

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4, 1, 2, + \frac{1}{2}

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Solution

The correct option is B $4, 1, 1, - \frac{1}{2}$
The valence node shell configuration is $4 s^{2} 4 p^{5}$ for the last electron $n = 4, l = 1$ .

$m = - 1, 0$ or $+ 1, s = + \frac{1}{2}$ or $- \frac{1}{2}$ .

Hence, $4, 1, 1, - \frac{1}{2}$

Therefore, option B is correct.

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