You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Quantum Numbers

Which of the ...

Question

Which of the following sets of quantum numbers is not possible for an electron?

n = 1, l = 0, m_{l} = 0, m_{s} = - \frac{1}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

n = 2, l = 1, m_{l} = 0, m_{s} = - \frac{1}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

n = 1, l = 1, m_{l} = 0, m_{s} = + \frac{1}{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

n = 2, l = 1, m_{l} = 0, m_{s} = + \frac{1}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $n = 1, l = 1, m_{l} = 0, m_{s} = + \frac{1}{2}$
The set of quantum numbers $n = 1, l = 1, m_{l} = 0, m_{s} = + \frac{1}{2}$ is not possible for an electron.
When $n = 1$ , $l$ can have a maximum value of 0. It cannot be 1.

For a given value of n, the possible values of $l$ are $0, 1, 2, . . . ., (n - 1)$ .

Suggest Corrections

Similar questions

Q. Arrange the electrons represented by the following sets of quantum numbers in decreasing order of energy.
(i)

n = 4, l = 0, m_{l} = 0, m_{s} = + \frac{1}{2}

(ii)

n = 3, l = 1, m_{l} = 1, m_{s} = - \frac{1}{2}

(iii)

n = 3, l = 2, m_{l} = 0, m_{s} = + \frac{1}{2}

(iv)

n = 3, l = 0, m_{l} = 0, m_{s} = - \frac{1}{2}

Q. Explain giving reasons which of the following sets of quantum numbers are not possible.
(a )

n = 0

l = 0

m_{1} = 0

m_{s} = + 1 / 2

(b)

n = 1

l = 0

m_{1} = 0

m_{s} = - 1 / 2

(c)

n = 1

l = 1

m_{1} = 0

m_{s} = + 1 / 2

(d)

n = 2

l = 1

m_{1} = 0

m_{s} = - 1 / 2

(e)

n = 2

l = 3

m_{1} = - 3

m_{s} = + 1 / 2

(f)

n = 3

l = 1

m_{1} = 0

m_{s} = + 1 / 2

Q. The quantum number of four electrons are given below:
I.

n = 4, l = 2, m_{l} = - 2, m_{s} = - 1 / 2

II.

n = 3, l = 2, m_{l} = 1, m_{s} = + 1 / 2

III.

n = 4, l = 1, m_{l} = 0, m_{s} = + 1 / 2

IV.

n = 3, l = 1, m_{l} = 1, m_{s} = - 1 / 2

The correct order of their increasing energies will be:

Question 18

Out of the following pairs of electrons, identify the pairs of electrons present in degenerate orbitals.

(a) (i) $n = 3, l = 2, m_{l} = - 2, m_{s} = - \frac{1}{2}$ (ii) $n = 3, l = 2, m_{l} = - 1, m_{s} = - \frac{1}{2}$

(b) (i) $n = 3, l = 1, m_{l} = 1, m_{s} = + \frac{1}{2}$ (ii) $n = 3, l = 2, m_{l} = - 1, m_{s} = + \frac{1}{2}$

(d) (i) $n = 3, l = 2, m_{l} = + 2, m_{s} = - \frac{1}{2}$ (ii) $n = 3, l = 2, m_{l} = + 2, m_{s} = + \frac{1}{2}$

Explain, giving reasons, which of the following sets of quantum numbers are not possible.
a) n = 0 l = 0 ml = 0 $m, = + \frac{1}{2}$
b) n = 1 l = 0 ml = 0 $m, = - \frac{1}{2}$
c) n = 1 l = 1 ml = 0 $m, = + \frac{1}{2}$
d) n = 2 l = 1 ml = 0 $m, = - \frac{1}{2}$
e) n = 3 l = 3 ml = – 3 $m, = + \frac{1}{2}$
f) n = 3 l = 1 ml = 0 $m, = + \frac{1}{2}$

Join BYJU'S Learning Program

Which of the following sets of quantum numbers is not possible for an electron?

The correct option is C n=1,l=1,ml=0,ms=+12The set of quantum numbers n=1,l=1,ml=0,ms=+12 is not possible for an electron. When n=1, l can have a maximum value of 0. It cannot be 1. For a given value of n, the possible values of l are 0,1,2,....,(n−1).