Which of the following sets of quantum numbers is not valid?

n = 1, l = 2

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n = 2, m = 1

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n = 3, l = 0

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n = 4, l = 2

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Solution

The correct option is A n = 1, l = 2
For a given ‘n’ the possible values of ‘l’ will be less than ‘n’. So when n = 1, the possible values= 0 but not l = 2.

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Q. Sum upto

n

terms for series

\frac{C_{0}}{1 \cdot 2} + \frac{C_{1}}{2 \cdot 3} + \frac{C_{2}}{3 \cdot 4} + \dots

is
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Which of the following sets of quantum numbers is not valid?

The correct option is A n = 1, l = 2For a given ‘n’ the possible values of ‘l’ will be less than ‘n’. So when n = 1, the possible values= 0 but not l = 2.

The correct option is A n = 1, l = 2
For a given ‘n’ the possible values of ‘l’ will be less than ‘n’. So when n = 1, the possible values= 0 but not l = 2.