Question

Which of the following setups is correct to calculate the weight (in g) of KCIO3 produced fromthe reaction of 0.150 moles of Cl2? 3CI2+6KOH-5KCI+ KCIO3 + 3H20 (a) 0.150 moles Cl2 x1 mole KCIO 3/3 moles Cl2x 122.5 g/1 mole KCIO3 (b) 0.150 moles CI2 x1 mole KCIO 3/3 moles Cl2 x 1 mole KClO3/122.5 g (c) 0.150 moles Cl2 x 3 moles Cl2/1 mole KCIO 3 x 122.5 g/1 mole KCIO3 (d) 0.150 moles Cl2x3 moles Cl2/1 mole KCIO 3 x1 mole KclO3/122.5 g

Answer 1