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Lewis Kossel Structure

Which of the ...

Question

Which of the following should be most stable?

H e_{2}

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H_{2}

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H e_{2}^{+}

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H_{2}^{+}

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Solution

The correct option is B $H_{2}$
Bonding orbitals have 2 electrons in $H_{2}$ . The configuration is $1 s^{2}$ . Rest all have electrons in antibonding orbitals.
For $H e_{2}$ , electronic configuration is $1 s^{2} * 1 s^{2}$ .
For $H e_{2}^{+ 1}$ , electronic configuration is $1 s^{2} * 1 s^{1}$ .
For $H_{2}^{+ 1}$ , electronic configuration is $1 s^{1}$ . This has fractional bond order. Hence, it is unstable.

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Similar questions

Question 19

Which of the following statement is not correct from the view point molecular orbital theory?

(a) $B e_{2}$ is not a stable molecule

(b) $H e_{2}$ is not stable but $H e_{2}^{+}$ is expected to exist.

(d) The order of energies of molecular orbitals in $N_{2}$ molecule is

$σ 2 s < σ^{*} 2 s < σ 2 p_{z} < (π^{*} 2 p_{x} ≃ π^{*} 2 p_{y}) < σ^{*} 2 p_{z}$

H e_{2}, H e_{2}^{+}

H e_{2}^{2 +}

The correct statement with regard to $H_{2}^{+}$ & $H_{2}^{-}$ is

H_{2}

{H e}_{2}^{+}

{L i}_{2}

{B e}_{2}

B_{2}

C_{2}

N_{2}

O_{2}^{-}

F_{2}

H = 1

H e = 2

L i = 3

B e = 4

B = 5

C = 6

N = 7

O = 8

F = 9

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