Question

Which of the following show $p\pi -d\pi$ bonding?

• A. $N{O}_3^{-}$
• B. $S{O}_3^{2-}$
• C. $B{O}_3^{3-}$
• D. $C{O}_3^{2-}$

Answer 1

The correct option is B $S{O}_3^{2-}$

To find the element, it must contain $d-$orbital.

Only 'sulphur' contain $d-$orbitals. Thus, it is capable to form $p\pi -d\pi$-bond.

All other elements contain only $s$ and $p-$orbitals.

Hence, option B is correct.