The correct option is
B Both (1) & (2)
The possible oxidation states of
Os and
Ru are :-
Os⇒−4,−2,−1,0,+1,+2,+3,+4,+5,+6,+7,+8
Ru⇒−4,−2,0,+1,+2,+3,+4,+5,+6,+7,+8
Therefore, both Os and Ru show highest oxidation number of +8.
Therefore, (C) is the correct answer.