Question

Which of the following solution has the lowest freezing point temperature?

• A. 0.1 M $MgC{l}_2$
• B. 0.1 M $HCl{O}_4$
• C. 0.1 M $N{H}_{4}OH$
• D. 0.1 M $KOH$
• E. 0.1 M $LiN{O}_3$

Answer 1

The correct option is A 0.1 M $MgC{l}_2$

Since all of them have the same molar concentration, compound breaks up into the most individual particles.

$MgC{l}_2\to M{g}_{2+}+C{l}_{1-}+C{l}^{1-}$ (3 particles)

$HCl{O}_4\to H^{1+}+Cl{O}_4^{1-}$(2 particles)

$N{H}_{4}OH\to N{H}_4^{1+}+O{H}^{1-}$(2 particles)

$KOH\to K^{1+}+O{H}^{1-}$ (2 particles)

$LiN{O}_3\to L{i}^{1+}+N{O}_3^{1-}$ (2 particles)

Therefore ans. is $MgC{l}_2$.