Which of the following solutions shows maximum depression in freezing point?

0.5 M L i_{2} S O_{4}

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1 M N a C l

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0.5 M A l_{2} (S O_{4})_{3}

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0.5 M B a C l_{2}

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Solution

The correct option is A $0.5 M A l_{2} (S O_{4})_{3}$
$T_{f} = i K_{f} m$

Depression in freezing point will be maximum for the compound having maximum van't Hoff factor $i$ which is maximum for $A l_{2} (S O_{4})_{3}$ which furnishes 5 ions in the solution, therefore $i = 5$ hence, it will have maximum depression in freezing point in case of the same concentration.

Here, in case of $A l_{2} S O_{4}$ and $N a C l$ , $A l_{2} S O_{4}$ have higher $i \times C$ value.

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