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Question

Which of the following species are paramagnetic in nature?

A
F2
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B
OF
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C
NO
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D
B2
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Solution

The correct options are
B NO
C OF
D B2

The molecular orbital configuration of F₂ (18 electrons) is:

(σ1s)² (σ*1s)² (σ2s)² (σ*2s)² (σ2pz)² (π2px)² (π2py)² (π*2px)² (π*2py)².

Since, there is no unpaired electron, F₂ is diamagnetic in nature.


The molecular orbital configuration of B₂ (10 electrons) is:

(σ1s)² (σ*1s)² (σ2s)² (σ*2s)² (π2px(π2py

There are two unpaired electrons, so B₂ is paramagnetic.


The molecular orbital configuration of NO (13 electrons) is:

(σ1s)² (σ*1s)² (σ2s)² (σ*2s)² (π2px)² (π2py)² (σ2pz)¹

There is one unpaired electron, so NO is paramagnetic.


The molecular orbital configuration of OF (17 electrons) is:

(σ1s)² (σ*1s)² (σ2s)² (σ*2s)² (σ2pz)² (π2px)² (π2pzy)² (π*2px)² (π*2py)¹.

There is one unpaired electron, so OF is paramagnetic.


Hence, options B, C and D are correct.

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