Which of the following species has same number of unpaired electrons ?

C r^{3 +}

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M n^{2 +}

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F e^{3 +}

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C u^{2 +}

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Solution

The correct options are
B $M n^{2 +}$
C $F e^{3 +}$
1. $C r - 24$ electrons are present: $[A r]$ $3 d^{5} 4 s^{1}$ . $C r^{3 +}$ means 3 electrons are lost (1electron from 4s and 2 electrons from 3d),so totally 3 unpaired electrons are present.
2. $M n - 25$ electrons are present: $[A r] 3 d^{5} 4 s^{2}$ . $M n^{2 +}$ means 2 electrons are lost (2 electron from 4s),so totally 5 unpaired electrons are present.
3. $F e - 26$ electrons are present: $[A r] 3 d^{6} 4 s^{2}$ . $F e^{3 +}$ means 3 electrons are lost (1electron from 4s and 1 electrons from 3d),so totally 5 unpaired electrons are present.
4. $C u - 29$ electrons are present: $[A r] 3 d^{10} 4 s^{1}$ . $C u^{+}$ means 2 electrons are lost (1electron from 4s and 1 electrons from 3d),so totally 1 unpaired electrons are present.
so the same number of unpaired electrons are present in $M n^{2 +}$ , $F e^{3 +}$ i.e 5 unpaired electrons.
Hence options B & D are correct.

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Question 14

The pair of ions having same electronic configuration is.............

(a) $C r^{3 +}, F e^{3 +}$ (b) $F e^{3 +}, M n^{2 +} +$ (c) $F e^{3 +}, C o^{3 +}$ (d) $S C^{3 +}, C r^{3 +}$

M n^{3 +}

C r^{3 +}

V^{3 +}

Write down the number of 3d electrons in each of the following ions:

Ti²⁺, V²⁺, Cr³⁺, Mn²⁺, Fe²⁺, Fe³⁺, CO²⁺, Ni²⁺ and Cu²⁺.

Indicate how would you expect the five 3d orbitals to be occupied for these hydrated ions (octahedral).

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