Which of the following species have a bond order of $3$ ?

C O

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C N^{-}

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N O^{+}

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O_{2}^{+}

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Solution

The correct options are
A $C O$
B $C N^{-}$
C $N O^{+}$
$B o n d o r d e r =$ $\frac{n u m b e r o f b o n d i n g s ¯ e - n u m b e r o f A n t i b o n d i n g s ¯ e}{2}$
$\to$ Greater the bond order, more stable the molecule or the ion.
$\to$ Also, greater the bond order, shorter the bond length and greater the bond energy.
$\to$ $C O = \frac{10 - 4}{2} = 3$
$\to$ ${C N}^{-} = \frac{10 - 4}{2} = 3$
$\to$ ${N O}^{+} = \frac{10 - 4}{2} = 3$
$\to$ $O_{2}^{+} = \frac{10 - 5}{2} = 2.5$

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