The correct options are
A AsF3
C AsF+4
D AsF−6
A) AsF3 is trigonal pyramidal, where all F atoms are present in axial position. So, all bond lengths are equal.
B) The shape of AsF−4 is See-saw. So, two axial bonds are longer than the two equitorial bonds.
C) AsF+4 is tetrahedral in shape. All bond lengths are equal.
d) AsF−6 is octahedral in shape. All bond lengths are equal to each other in a octahedral.