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Question

Which of the following species is not paramagnetic?


A

O2

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B

B2

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C

NO

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D

CO

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Solution

The correct option is D

CO


Explanation for the correct option:

Option (d):

  • According to Molecular orbital theory, if there are unpaired electrons in orbitals then it is said to be paramagnetic in nature.
  • If there are no unpaired electrons then it is called diamagnetic.
  • There are 14 electrons in CO molecule.
  • The electronic configuration of CO is (σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(π2px2=π2py2)(σ2pz)2
  • Since there is no unpaired electron in bonding and anti-bonding orbitals, COmolecule is diamagnetic.

Explanation for the incorrect option:

Option (a):

  • There are 16 electrons in O2molecule.
  • The electronic configuration of O2 is (σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(σ2pz)2(π2px2=π2py2)(π*2px1=π*2py1)
  • There are two unpaired electrons in π*2px1 and π*2py1 molecular orbitals.
  • So, this is paramagnetic in nature.

Option (b):

  • There are 10 electrons in B2molecule.
  • The electronic configuration of B2 is (σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(π2px1=π2py1)
  • There are two unpaired electrons in π2px1 and π2py1 molecular orbitals.
  • So, this is paramagnetic in nature.

Option (c):

  • There are 15 electrons in NOmolecule.
  • The electronic configuration of NO is (σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(π2px2=π2py2)(σ2pz)2(π*2px1)
  • There is one unpaired electron in π*2px1 molecular orbitals.
  • So, this is paramagnetic in nature.

Final answer:

Hence, option (d) is the correct answer.


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